#include<stdio.h> int main() { int a[5]= {5,4,6,8,9}; int *p=&a[0]; int i; for(i=0; i<5; i++) printf("\nArray[%d] is %d ",i,*(p+i)); for(i=0; i<5; i++) printf("\n %d at %u ",*(p+i),(p+i)); return 0; }
OUTPUT
Array[0] is 5 Array[1] is 4 Array[2] is 6 Array[3] is 8 Array[4] is 9 5 at 2686708 4 at 2686712 6 at 2686716 8 at 2686720 9 at 2686724